Physics Help

[AsuraSky]

Any help on this problem will be greatly appreciated

In Fig. 11-39 a cylinder having a mass of 2.0 kg can rotate about its central axis through point O. Forces are applied as shown. F1 = 12.0 N, F2 = 8.0 N, F3 = 4.0 N, and F4 = 5.0 N. Also, R1 = 5.0 cm and R2 = 12 cm.


Figure 11-39

Find the magnitude and direction of the angular acceleration of the cylinder. (During the rotation, the forces maintain their same angles relative to the cylinder.)

Here the work i did (maybe find what i did wrong or something >.>)
net torque = I*(angular acceleration)

net torque = .12*(12*sin 90) + .12*(8*sin 90) + .12*(4*sin 24.624) = 2.6
I = .5*M*R^2 = .5*2.0*.12^2 = .0144

2.6 = .0144*(angular acceleration)
(angular acceleration) = 180.55556 rad/s^2

This answer is wrong so if anyone can help me figure out what I did wrong in my calculations or any help at all will be greatly appreciated

[xele]

why do you plus everything, when there is something called clockwise and anti clockwise.

[AsuraSky]

hmm good point...i'll change my signs around and see what i get